j^2+39=16j

Solution for j^2+39=16j equation:

Simplifying
j2 + 39 = 16j

Reorder the terms:
39 + j2 = 16j

Solving
39 + j2 = 16j

Solving for variable 'j'.

Reorder the terms:
39 + -16j + j2 = 16j + -16j

Combine like terms: 16j + -16j = 0
39 + -16j + j2 = 0

Factor a trinomial.
(3 + -1j)(13 + -1j) = 0

Subproblem 1
Set the factor '(3 + -1j)' equal to zero and attempt to solve:

Simplifying
3 + -1j = 0

Solving
3 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1j = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1j = 0 + -3
-1j = 0 + -3

Combine like terms: 0 + -3 = -3
-1j = -3

Divide each side by '-1'.
j = 3

Simplifying
j = 3
Subproblem 2
Set the factor '(13 + -1j)' equal to zero and attempt to solve:

Simplifying
13 + -1j = 0

Solving
13 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -13 + -1j = 0 + -13

Combine like terms: 13 + -13 = 0
0 + -1j = 0 + -13
-1j = 0 + -13

Combine like terms: 0 + -13 = -13
-1j = -13

Divide each side by '-1'.
j = 13

Simplifying
j = 13
Solution
j = {3, 13}